InterviewSolution
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InterviewSolution
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Equation of the line passing through `(1, 1, 1)` and parallel to the plane `2x +3y + z + 5 =0` isA. `(x-1)/1=(y-1)/2=(z-1)/1`B. `(x-1)/(-1)=(y-1)/1=(z-1)/(-1)`C. `(x-1)/3=(y-1)/2=(z-1)/1`D. `(x-1)/2=(y-1)/3=(z-1)/1` |
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Answer» Correct Answer - B Clearly, all lines in the given optics pass through (1,1,1). We know that a line is parallel to a plane if the normal to the plane is perpendicular to the line. We obsere that the vector normal to the given plane is `vecn=2hati+3hatj+hatk` and the line in option b is parallel to the vector `vecb=-hati+hatj-hatk` such that `vecb.vecn=-2+3-1=0` i.e. `vecb_|_vecn`. Hence option b is correct. |
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