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The equation of the plane contaiing the lines `vecr=veca_(1)+lamda vecb` and `vecr=veca_(2)+muvecb` isA. `[(vecr, veca, vecb)]=0`B. `[(vecr,veca,vecb)]=veca.vecb`C. `[(veca,vecb,veca)]=veca.vecb`D. none of these |
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Answer» Correct Answer - A The required plane passes through the points having position vectors `veca` and `vecb`. It is perpendicular to `vecaxxvecb`. So theequation of the plane is `(vecr-veca).(vecaxxvecb)=0impliesvecr.(vecaxxvecb)=veca.(vecaxxvecb)implies[(vecr,veca,vecb)]=0` |
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