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Equation of the line passing through the point (2, 3) and parallel to the line joining the points (4, 1) and (-2,2) is(A) x + 6y + 12 = 0(B) x + 6y - 12 = 0(C) x + 6y + 16 = 0(D) x + 6y + 16 = 0 |
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Answer» Correct option (D) x + 6y + 16 = 0 Explanation : Slope of the line joining the points (4, 1) and (-2,2) is 2 - 1/-2 - 4(= -1/6) Hence, by Theorem 2.2, the equation of the given line is y + 3 = 1/6(x - 2) x + 6y + 16 = 0 |
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