Equation of the plane passing through the line x−12=y+1−1=z−34 a – InterviewSolution

1.	Equation of the plane passing through the line x−12=y+1−1=z−34 and perpendicular to the plane x+2y+z=12 is given by ax+by+cz+4=0 then -
Answer» Equation of the plane passing through the line $\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z - 3}{4}$ and perpendicular to the plane $x + 2 y + z = 12$ is given by $a x + b y + c z + 4 = 0$ then -

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