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Equation represents a pair of parallel lines and find distance between them. `4x^2+4xy+y^2-6x-3y-4=0`

Answer» `4x^2+4xy+y^2-6x-3y-4=0`
`4x^2+x(4y-6)+y^2-3y-4=0`
`x=((6-4y)pmsqrt(16y^2+36-48y-4(4y^2-12y-16)))/(2*4)`
`x=((6-4y)pmsqrt(100))/8`
`x=((6-4y)pm10)/8`
`2x-y-4=0`
`2x+y+1=0`
distance between lines`=|(-4-1)/sqrt(2^2+1^2)|`
`=|(-5)/sqrt5|`
`=sqrt5`.


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