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Equation represents a pair of parallel lines and find distance between them. `4x^2+4xy+y^2-6x-3y-4=0` |
Answer» `4x^2+4xy+y^2-6x-3y-4=0` `4x^2+x(4y-6)+y^2-3y-4=0` `x=((6-4y)pmsqrt(16y^2+36-48y-4(4y^2-12y-16)))/(2*4)` `x=((6-4y)pmsqrt(100))/8` `x=((6-4y)pm10)/8` `2x-y-4=0` `2x+y+1=0` distance between lines`=|(-4-1)/sqrt(2^2+1^2)|` `=|(-5)/sqrt5|` `=sqrt5`. |
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