Equations of the line passing through `(-1,2,-3)` and parallel to the line `(x-2)/3 = (y+1)/(-5) = (z+3)/(-7)` areA. `(x-1)/3=(y+2)/(-5)=(z-3)/(-7)`B. `(x+1)/3=(2-y)/5=(z=3)/(-7)`C. `(x+1)/(-3)=(y-2)/(-5)=(z+3)/7`D. `3(x-1)=5(y+1)=-7(z+3)`

Equations of the line passing through `(-1,2,-3)` and parallel to the

1.	Equations of the line passing through `(-1,2,-3)` and parallel to the line `(x-2)/3 = (y+1)/(-5) = (z+3)/(-7)` areA. `(x-1)/3=(y+2)/(-5)=(z-3)/(-7)`B. `(x+1)/3=(2-y)/5=(z=3)/(-7)`C. `(x+1)/(-3)=(y-2)/(-5)=(z+3)/7`D. `3(x-1)=5(y+1)=-7(z+3)`
Answer» Correct Answer - B

Discussion

No Comment Found

Related InterviewSolutions

Length of perpendicular from the point `(3,2,1)` to the line `(x-7)/2 = (y-7)/(-2) = (z - 6)/(-3)` isA. `sqrt(46)`B. `sqrt(47)`C. `sqrt(48)`D. `sqrt(49)`
Equation of the plane containing the line ` L_(1) : (x-1)/3 = (y+6)/4 = (z+1)/2 ` , parallel to the line `L_(2) : (x-2)/2 = (y-1)/(-3)= (z+4)/5` , is `26 x - 11y - 17 z ` = p where : p =A. 109B. 110C. 111D. 112
Line ` (x-2)/(-2) = (y+1)/(-3) = (z-5)/1 ` intersects the plane `3x+4y+z = 3 ` in the pointA. `(23/7,29/7,38/7)`B. `(29/7,38/7,23/7)`C. `(38/7,29/7,23/7)`D. `(1,2,8)`
If the line `(x-4)/(1)=(y-2)/(1)=(z-k)/(2)` lies exactly on the plane `2x-4y+z=7`, the value of k isA. 7B. `-7`C. no real valuesD. 4
Distance from the point `(-3,2,5)` to the point where the line `(x+3)/2= (y-2)/2=(z-5)/2` meets the plane `x+y +2z = 3` isA. `7/18`B. `8/17`C. `17/8`D. `18/7`
Distance of the points of intersection of the line `(x-3)/(1)=(y-4)/(2)=(z-5)/(2)and` plane `x+y+z=2` from the point (3,4,5) is
The point at which the line joining the points `(2, -3, 1) and (3, -4, -5)` intersects the plane `2x+y+z=7` isA. `(1,2,-7)`B. `(1,-2,7)`C. `(-1,2,7)`D. `(1,2,7)`
Line `(x-1)/2= (y-2)/3=(z-3)/4` intersects the plane `3x+6y+5z = 0 ` in the point A . Then the direction ratios of the line OA areA. `1,6,-8`B. `8,6,-1`C. `6,8,1`D. `8,1,-6`
Distance of the point of intersection of the line `(x-2)/3=(y+1)/4=(z-2)/12` and the plane `x-y+z = 5 ` from the point `(-1,-5,-10)` is
Equations of the line joining `(2,-3,1)and (3,-4,-5)` areA. `(x-2)/3 =(y+3)/(-4) = (z-1)/(-5)`B. `(x-3)/2=(y+4)/(-3) (z+5)/1`C. `2-x = y +3 = (z-1)/6`D. `(x-2)/3 = (y+4)/(-3) = (z-1)/(-1)`

Equations of the line passing through `(-1,2,-3)` and parallel to the line `(x-2)/3 = (y+1)/(-5) = (z+3)/(-7)` areA. `(x-1)/3=(y+2)/(-5)=(z-3)/(-7)`B. `(x+1)/3=(2-y)/5=(z=3)/(-7)`C. `(x+1)/(-3)=(y-2)/(-5)=(z+3)/7`D. `3(x-1)=5(y+1)=-7(z+3)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment