Equilibrium constant K_(c) for the reaction , N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g) at 500 K is 0.061, At particular time ,the analysis shows that the composition of the reaction mixture is 3.0 mol L^(-1) of H_(2), 0.50 mol L^(-1) of NH_(3) .Is the reaction at equilibrium ?

Equilibrium constant K_(c) for the reaction , N_(2) (g) + 3 H_(2) (g)

1.	Equilibrium constant K_(c) for the reaction , N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g) at 500 K is 0.061, At particular time ,the analysis shows that the composition of the reaction mixture is 3.0 mol L^(-1) of H_(2), 0.50 mol L^(-1) of NH_(3) .Is the reaction at equilibrium ?
Answer» SOLUTION :The given reaction is `: N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g)` According to available data `N_(2) = [3.0] , H_(2) = [2,0] , NH_(3) = [0.50]` `Q_(C) = ([NH_(3) (g)]^(2))/([N_(2) (g)] [H_(2) (g)]^(3)) = ([0.50]^(2))/([3.0][2.0]) = (0.25)/(24) = 0.0104`