Equilibrium constant, K_c for the reaction N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) at 500 K is 0.061 At a particular time, the analysis shows that composition of the reaction mixture is 3.0 mol L^(-1) N_2, 2.0 mol L^(-1) H_2,and 0.5 mol L^(-1) NH_3. Is the reaction at equilibrium ? If not in which direction does the reaction tend to proceed to reach equilibrium ?

Equilibrium constant, K_c for the reaction N_(2(g)) + 3H_(2(g)) hArr 2

1.	Equilibrium constant, K_c for the reaction N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) at 500 K is 0.061 At a particular time, the analysis shows that composition of the reaction mixture is 3.0 mol L^(-1) N_2, 2.0 mol L^(-1) H_2,and 0.5 mol L^(-1) NH_3. Is the reaction at equilibrium ? If not in which direction does the reaction tend to proceed to reach equilibrium ?
Answer» SOLUTION :`{:("Equilibrium reaction :",N_(2(G))+ , 3H_(2(g)) HARR , 2NH_(3(g))),("At t time composition :",3.0,2.0,0.5):}` At t time the reaction quotient Q of composition of reaction MIXTURE is, `Q_c=[NH_3]^2/([N_2][H_2])^3=(0.5)^2/((3.0)(2)^3)`=0.0104 `therefore (Q_c=0.0104) lt (K_c=0.061)` Here, `Q_c lt K_c` , the reaction will proceed in the direction of the products (Forward reaction till = `Q_c=K_c`) .