Equilibrium constant K_(C) for the reaction, N_(2(g))+3H_(2(g))hArr2NH_(3(g)) at 500K is 0.061. At particular time, the analysis shows that the composition of the reaction mixture is 3.0" mol L"^(-1) of N_(2),2.0" mol L"^(-10 of H_(2),0.50" mol L"^(-1) of NH_(3).is the reaction at equilibrium ?

Equilibrium constant K_(C) for the reaction, N_(2(g))+3H_(2(g))hArr2N

1.	Equilibrium constant K_(C) for the reaction, N_(2(g))+3H_(2(g))hArr2NH_(3(g)) at 500K is 0.061. At particular time, the analysis shows that the composition of the reaction mixture is 3.0" mol L"^(-1) of N_(2),2.0" mol L"^(-10 of H_(2),0.50" mol L"^(-1) of NH_(3).is the reaction at equilibrium ?
Answer» Solution :The given REACTION is `N_(2(g))+3H_(2(g))hArr2NH_(3(g))` According to available data `N_(2)=(3.0)H_(2)=(2.0)NH_(3)=(0.50)` `Q_(C)=((NH_(3(g)))^(2))/([N_(2(g))][H_(2(g))]^(3))` `=([0.50]^(2))/((3.0)(2.0))=(0.25)/(24)=0.0104`