Equilibrium constant, K_(c) the reaction N_(2)(g)+3H_(2) (g) Leftrightarrow 2NH_(3) (g)" is "2 xx 10^(-2) mol^(-2) lit^(2). What is the value of K_(c) for the reaction 2NH_(3) (g) Leftrightarrow N_(2) (g)+3H_(2)(g)?

Equilibrium constant, K_(c) the reaction N_(2)(g)+3H_(2) (g) Leftright

1.	Equilibrium constant, K_(c) the reaction N_(2)(g)+3H_(2) (g) Leftrightarrow 2NH_(3) (g)" is "2 xx 10^(-2) mol^(-2) lit^(2). What is the value of K_(c) for the reaction 2NH_(3) (g) Leftrightarrow N_(2) (g)+3H_(2)(g)?
Answer» SOLUTION :`N_(2)(G)+3H_(2) (g) Leftrightarrow 2NH_(3) (g)`, `K_(C)= ([NH_(3)]^(2))/[N_(2)][H_(2)]^(3)=2 xx 10^(-2)" mol"^(2) lit^(2)` `NH_(3) (g) Leftrightarrow N_(2) (g)+3H_(2)(g), K_(2)=?` `K_(2)=([N_(2)] [H_(2)]^(3))/([NH_(3)]^(2))=(1)/(K_(C)0=(1)/(2 xx 10^(-2))=50 mol^(2) lit^(-2)`