Equilibrium constant K_(X), for the reaction H_(2)(g)+I_(2) (g) Leftrightarrow 2HI(g), is 49. What is the value of K_(C) for the reaction 1/2 H_(2)(g)+1/2I_(2) (g) Leftrightarrow HI(g) and 2HI (g) Leftrightarrow H_(2) (g)+I_(2) (g)?

Equilibrium constant K_(X), for the reaction H_(2)(g)+I_(2) (g) Leftri

1.	Equilibrium constant K_(X), for the reaction H_(2)(g)+I_(2) (g) Leftrightarrow 2HI(g), is 49. What is the value of K_(C) for the reaction 1/2 H_(2)(g)+1/2I_(2) (g) Leftrightarrow HI(g) and 2HI (g) Leftrightarrow H_(2) (g)+I_(2) (g)?
Answer» SOLUTION :`H_(2) (g)+I_(2) Leftrightarrow 2HI(g)` `K=([HI]^(2))/([H_(2)] [I_(2)])=49` `1/2 H_(2) (g)+1/2 I_(2) (g) Leftrightarrow HI (g), K_(1)=?` `K_(1)=K^(1/2)=sqrt(K)=sqrt(49)=7` `2HI (g) Leftrightarrow H_(2) (g)+I_(2) (g), K_(2)=?` `K_(C)` for the REACTION `2HI(g) Leftrightarrow H_(2)(g)+I_(2)(g)` is `K_(2)=1/K =(1)/(49)=2.04 xx 10^(-2)`