1.

Equilibrium constant of following reaction is 0.5. CO_((g)) + 2H_(2(g)) hArr CH_3OH_((g)) at equilibrium [CO]=0.18 mol L^(-1) and [H_2] = 0.22 mol L^(-1)Calculate the concentration of CH_3OH.

Answer»

SOLUTION :`4.356xx10^(-3) ("mol L"^(-1))^(-2)`


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