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Equilmolar concentrations of H_(2) and I_(2) are heated to equilibrium in a 2 litre flask . At equilibrium , the forward and the backward rate constants are found to be equal . What percentage of intial concentration of H_(2) has reacted at equilibrium ? |
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Answer» `33 %` ` K= (x^(2))/((1-x)/2 xx (1-x)/2 )=(4 x^(2))/(1-x)^(2) approx4x^(2)` But `K= (k_(f))/(k_(b))=1` `:. 4"" x^(2)=1 or x^(2) = 1//4 or x = 1//2 , i.e., 50%` |
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