Equimolar mixture of two gases A2 and B2 is taken in a rigid vessel at temperature 300 K. The gases react according to the given equations: A2(g)⇌2A(g) KP1=? B2(g)⇌2B(g) KP2=? A2(g)+B2(g)⇌2AB(g) KP3=2 If the initial pressure in the container was 2 atm and final pressure developed at equilibrium is 2.75 atm in which equilibrium partial pressure of gas AB was 0.5 atm, calculate the ratio of KP2KP1 (Given: degree of dissociation of B2 is greater than A2)

Equimolar mixture of two gases A2 and B2 is taken in a rigid vessel at

1.	Equimolar mixture of two gases A2 and B2 is taken in a rigid vessel at temperature 300 K. The gases react according to the given equations: A2(g)⇌2A(g) KP1=? B2(g)⇌2B(g) KP2=? A2(g)+B2(g)⇌2AB(g) KP3=2 If the initial pressure in the container was 2 atm and final pressure developed at equilibrium is 2.75 atm in which equilibrium partial pressure of gas AB was 0.5 atm, calculate the ratio of KP2KP1 (Given: degree of dissociation of B2 is greater than A2)
Answer» Equimolar mixture of two gases $A_{2}$ and $B_{2}$ is taken in a rigid vessel at temperature $300 K$ . The gases react according to the given equations: $A_{2} (g) ⇌ 2 A (g) K_{P_{1}} = ?$ $B_{2} (g) ⇌ 2 B (g) K_{P_{2}} = ?$ $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g) K_{P_{3}} = 2$ If the initial pressure in the container was 2 atm and final pressure developed at equilibrium is 2.75 atm in which equilibrium partial pressure of gas AB was 0.5 atm, calculate the ratio of $\frac{K_{P_{2}}}{K_{P_{1}}}$ (Given: degree of dissociation of $B_{2}$ is greater than $A_{2}$ )

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