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Equimoler solulition of HF, HCOOH and HCN at 298 K have the values of Ka as `6.8xx10^(-4), 1.8xx10^(-4)` and `4.8xx10^(-9)` respectively, what will be the order of their acidic strength ?A. `HFgtHCIgtHCOOH`B. `HFgtHCOOHgtHCN`C. `HCIgtHFgtHCOOH`D. `HCOOHgtHCNgtHF` |
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Answer» Correct Answer - B acidic strength `alphaK_(a)` |
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