Equivalent conductance of saturated `BaSO_(4)` is 400 S `cm^(2) eq^(-1)` an d specific conductyance is 8 `xx10^(-5)S cm^(-1)`. Solubility product. `K_(sp)` of `BaSO_(4)` isA. `4xx10^(-8)`B. `1xx10^(-8)`C. `2xx10^(-4)`D. `1xx10^(-4)`

Equivalent conductance of saturated `BaSO_(4)` is 400 S `cm^(2) eq^(-1

1.	Equivalent conductance of saturated `BaSO_(4)` is 400 S `cm^(2) eq^(-1)` an d specific conductyance is 8 `xx10^(-5)S cm^(-1)`. Solubility product. `K_(sp)` of `BaSO_(4)` isA. `4xx10^(-8)`B. `1xx10^(-8)`C. `2xx10^(-4)`D. `1xx10^(-4)`
Answer» Correct Answer - B `lambda_(m)^(0)(BaSO_(4))=2xxlambda_(eq)^(0)(BaSO_(4))` `=2xx400=800` `lambda_(m)^(0)(BaSO_(4))=(kxx1000)/(M)` `M=(kxx1000)/(lambda_(m)^(0)BaSO_(4))` `=(8xx10^(-5)xx1000)/(800)=10^(-4)`

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Equivalent conductance of saturated `BaSO_(4)` is 400 S `cm^(2) eq^(-1)` an d specific conductyance is 8 `xx10^(-5)S cm^(-1)`. Solubility product. `K_(sp)` of `BaSO_(4)` isA. `4xx10^(-8)`B. `1xx10^(-8)`C. `2xx10^(-4)`D. `1xx10^(-4)`

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