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Equivalent mass of H_(3)PO_(2) when it disproportionates into PH_(3) " and" H_(3)PO_(3) is (Molecular mass=M) : |
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Answer» M (Change in OXIDATION number=2) `overset(+1)(H_(3)PO_(2) to overset(-3)(PH_(3)), " Eq. wt." = (M)/(4)` (Change in oxidation number=4) The EQUIVALENT mass of `H_(3)PO_(2)` in the PROCESS of disproportionation`=(M)/(2)+(M)/(4)=(3M)/(4)` |
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