1.

Equivalent mass of H_(3)PO_(2) when it disproportionates into PH_(3) " and" H_(3)PO_(3) is (Molecular mass=M) :

Answer»

M
`(M)/(2)`
`(M)/(4)`
`(3M)/(4)`

SOLUTION :`overset(+1)(H_(3)PO_(2))to overset(+3)(H_(3)PO_(3)), " Eq. wt. "=(M)/(2)`
(Change in OXIDATION number=2)
`overset(+1)(H_(3)PO_(2) to overset(-3)(PH_(3)), " Eq. wt." = (M)/(4)`
(Change in oxidation number=4)
The EQUIVALENT mass of `H_(3)PO_(2)` in the PROCESS of disproportionation`=(M)/(2)+(M)/(4)=(3M)/(4)`


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