1.

Equivalent weight of `FeS_(2)` in the half reaction `FeS rarr Fe_(2)O_(3) + SO_(2)` is :A. `M//10`B. `M//11`C. `M//8`D. `M//7`

Answer» Correct Answer - D
`S^(2-) rarr S^(4+) + 6e`
`2Fe^(2+) rarr (Fe^(3+))_(2) + 2e`
`FeS Fe_(2)O_(3) + SO_(2)`
involves a change of `7` electrons per mole.


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