1.

Equivalent weight of `H_(2)O_(2)` isA. 17B. 34C. 68D. 18

Answer» Correct Answer - A
`E.W.` of `H_(2)O_(2)=17`
`N=(30.36)/(17)=1.78N`
Volume strength `=5.6 xx` Normality ltbr. `=5.6 xx 1.78 =0` litre


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