1.

Equivalent weight of `H_(3)PO_(2)` when it disproportionates into `PH_(3)` and `H_(3)PO_(3)` is (mol.wt. of `H_(3)PO_(2)=M`)A. `M`B. `(3M)/(4)`C. `(M)/(2)`D. `(M)/(4)`

Answer» Correct Answer - B
`H_(3)PO_(2) rarr PH_(3)`
`P^(+)+4e^(-) rarr P^(3-)`
`:. Eq. wt. (H_(3)PO_(2))=M//4`
`H_(3)PO_(2) rarr H_(3)PO_(3)`
`P^(+) rarr P^(3+)+2e^(-)`
`:. Eq.wt. (H_(3)PO_(2))=M//2`
Hence,
Eq.wt. `(H_(3)PO_(2))=(M)/(4)+(M)/(2)=(3)/(4)M`


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