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Equivalent weight of `H_(3)PO_(2)` when it disproportionates into `PH_(3)` and `H_(3)PO_(3)` is (mol.wt. of `H_(3)PO_(2)=M`)A. `M`B. `(3M)/(4)`C. `(M)/(2)`D. `(M)/(4)` |
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Answer» Correct Answer - B `H_(3)PO_(2) rarr PH_(3)` `P^(+)+4e^(-) rarr P^(3-)` `:. Eq. wt. (H_(3)PO_(2))=M//4` `H_(3)PO_(2) rarr H_(3)PO_(3)` `P^(+) rarr P^(3+)+2e^(-)` `:. Eq.wt. (H_(3)PO_(2))=M//2` Hence, Eq.wt. `(H_(3)PO_(2))=(M)/(4)+(M)/(2)=(3)/(4)M` |
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