Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media are in ratio of:A. `3:5:15`B. `5:3:1`C. `5:1:3`D. `3:5:5`

Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media

1.	Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media are in ratio of:A. `3:5:15`B. `5:3:1`C. `5:1:3`D. `3:5:5`
Answer» Correct Answer - D `KMnO_(4)` can act as an O.A in acidic, basic and neutral mediums as follows : In acidic medium, `MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O` In basic medium `MnO_(4)^(-)+2H_(2)O+3Fe^(-)rarrMnO_(2)+4OH^(-)` In neutral medium `MnO_(4)^(-)+2H_(2)O+3Fe^(-)rarrMnO_(2)+4OH^(-)` Let molecular mass of `KMnO_(4)=M` `:.` Ratio of Eq mass of `KMnO_(4)` in acidic, basic and neutral mediums are `(M)/(5):(M)/(3):(M)/(3)or3:5:5`.

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Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media are in ratio of:A. `3:5:15`B. `5:3:1`C. `5:1:3`D. `3:5:5`

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