1.

Equivalent weight of `N_(2)` in the change `N_(2) rarr NH_(3)` isA. `28//6`B. `28`C. `28//2`D. `28//3`

Answer» Correct Answer - A
`6e+N_(2)^(0) rarr 2N^(3-)`
`EN_(2)=(28)/(6)`


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