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Escape velocity for earth surface is 11 km/s. If the radius of any planet is two times the radius of the earth but average density is same that of earth, then the escape velocity at the planet will be ........ |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a> km/s <br/>11km/s <br/>5.5 km/s<br/>15.5 km/s</p>Solution :`implies v_e=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((2GM)/R) =R sqrt(8/3piGrho)`<br/> `v_e <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> R ` (If `<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a> ` is <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> )</body></html> | |