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Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area `1.0xx10^(-7)m^(2)` carrying a current of `1.5xx10^(-19)`A. Assume the density of conduction electrons to be `9xx10^(28)m^(-3)`. |
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Answer» We know that `I="neA"" " vd` Where, I is the current, n is charge density, e is charge of electron and A is cross-section area. `V_(d)=I//"neA"` `=1.5xx10^(19)//9xx10^(28)xx1.6xx10^(-19)xx1xx10^(-7)` `V_(d)=10^(-3)ms^(-1)` This is the required average drift velocity. |
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