1.

Estimate the no. of electrons and protons in 200g of pure water

Answer»

HERE IS YOUR ANSWER:-

no. of moles of water =given mass / molar mass = 100/18 = 50/9 moles

total no. of atoms in 100g of water = 6.022 *1023 * 50/9 = 3.455 *1024 atoms

no. of ELECTRONS in 1 atom of H2O = 2*1 +8 = 10

total no. of elctrons = 3.455*1024 *10 = 3.455*1025 electrons..

charge in 1 electron = 1.6 *10-19

charge CARRIED by 3.455*1025 electrons = 1.6*10-19 * 3.455*1025= 5.528 * 106


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