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Estimate the total number of air molecules in a room of capacity 25m^(3) at a temperature of 27^(@)C. |
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Answer» SOLUTION :`T=27^(@)C+273=300K,k_(B)=1.38xx10^(-23)JK^(-1),V=25M^(3)` As Boltzmann.s CONSTANT, `k_(B)=R/Nimplies Rk_(B)N` Now , `PV=nRT=nk_(B)NT` The number of molecules in the room, `NN=(PV)/(k_(B)T)=(1.013xx10^(5)xx25)/(1.38xx10^(-23)xx300)` `=(25.325xx10^(5))/(414xx10^(-23))=0.06117xx10^(28)` `nN=6.1117xx10^(26)"molecules"` |
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