Estimatingthe following two numbers should be interesting. The first n

1.	Estimatingthe following two numbers should be interesting. The first numberwill tell you why radio engineers do not need to worry much aboutphotons! The second number tells you why our eye can never ‘countphotons’, even in barely detectable light.(a) The numberof photons emitted per second by a Medium wave transmitter of 10 kWpower, emitting radiowaves of wavelength 500 m.(b) The numberof photons entering the pupil of our eye per second corresponding tothe minimum intensity of white light that we humans can perceive(∼10−10W m−2).Take the area of the pupil to be about 0.4 cm2,and the average frequency of white light to be about 6 × 1014Hz.
Answer» Estimating the following two numbers should be interesting. The first number will tell you why radio engineers do not need to worry much about photons! The second number tells you why our eye can never ‘count photons’, even in barely detectable light. (a) The number of photons emitted per second by a Medium wave transmitter of 10 kW power, emitting radiowaves of wavelength 500 m. (b) The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can perceive (∼10⁻¹⁰ W m⁻²). Take the area of the pupil to be about 0.4 cm², and the average frequency of white light to be about 6 × 10¹⁴ Hz.

Estimatingthe following two numbers should be interesting. The first numberwill tell you why radio engineers do not need to worry much aboutphotons! The second number tells you why our eye can never ‘countphotons’, even in barely detectable light.(a) The numberof photons emitted per second by a Medium wave transmitter of 10 kWpower, emitting radiowaves of wavelength 500 m.(b) The numberof photons entering the pupil of our eye per second corresponding tothe minimum intensity of white light that we humans can perceive(∼10−10W m−2).Take the area of the pupil to be about 0.4 cm2,and the average frequency of white light to be about 6 × 1014Hz.

Answer»

Estimating
the following two numbers should be interesting. The first number
will tell you why radio engineers do not need to worry much about
photons! The second number tells you why our eye can never ‘count
photons’, even in barely detectable light.

(a) The number
of photons emitted per second by a Medium wave transmitter of 10 kW
power, emitting radiowaves of wavelength 500 m.

(b) The number
of photons entering the pupil of our eye per second corresponding to
the minimum intensity of white light that we humans can perceive
(∼10⁻¹⁰
W m⁻²).
Take the area of the pupil to be about 0.4 cm²,
and the average frequency of white light to be about 6 × 10¹⁴
Hz.

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