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Estimation of phosphorous: Second method: A known mass of compound is heated with fuming `HNO_(3)` or sodium peroxide `(Na_(2)O_(2)` in Carius tube which converts phosphorous to `H_(3)PO_(4)`. Magnesia mixture `(MgCl_(2)+NH_(4)Cl)` is then added, which gives the percipate of magnesium ammonium phosphate `(MgNH_(4).PO_(4))` which on heating gives magnesium pyrophosphate `(Mg_(2)P_(2)O_(7))` , which is weighted. Percentage of P`=("Atomic mass of P")/("Molecular mass of " Mg_(2)P_(2)O_(7)) xx ("Molecular mass of "Mg_(2)P_(2)O_(7) xx 100)/("Mass of compound")=(62)/(222) xx("Mass of " Mg_(2)P_(2)O_(7)xx 100)/("Mass of compound")` 0.12 gm of and organic compound containing phosphorus gave 0.22 gm of `Mg_(2)P_(2)O_(7)` by the usual analysis. Calculate the percentage of phosphorus in the compound.A. 25B. 9.25C. 801D. `51.20` |
Answer» Correct Answer - D |
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