Ethane burns in oxygen to form CO2 and H2O according to the equation

1.	Ethane burns in oxygen to form CO2 and H2O according to the equation :2C2H6 + 7O2 ---> 4CO2 + 6H2O If 1250 cc of oxygen is burnt with 300 cc of ethane. Calculate : (i) the volume of CO2 formed. (ii) the volume of unused O2.
Answer» The given equation is : 2C₂H₆ + 7O₂ ----> 4CO₂ + 6H₂O (i) So, according to above equation, 2 V (volume) of ethane reacts to give 4 V of carbon dioxide. So, 300 cc of ethane would give 600 cc of carbon dioxide. (ii) Also, 2 V(volumes) of ethane reacts with 7 V of oxygen. 300 cc of ethane is 2 V, so oxygen required for 300 cc of ethane is 300 x 7 /2 =1050 cc The remaining oxygen would be : 125O cc - 1050 cc = 200 cc

Ethane burns in oxygen to form CO2 and H2O according to the equation :2C2H6 + 7O2 ---> 4CO2 + 6H2O If 1250 cc of oxygen is burnt with 300 cc of ethane. Calculate : (i) the volume of CO2 formed. (ii) the volume of unused O2.

Answer»

The given equation is :

2C₂H₆ + 7O₂ ----> 4CO₂ + 6H₂O

(i) So, according to above equation, 2 V (volume) of ethane reacts to give 4 V of carbon dioxide.

So, 300 cc of ethane would give 600 cc of carbon dioxide.

(ii) Also, 2 V(volumes) of ethane reacts with 7 V of oxygen.

300 cc of ethane is 2 V, so oxygen required for 300 cc of ethane is

300 x 7 /2 =1050 cc

The remaining oxygen would be :

125O cc - 1050 cc = 200 cc