Ethyl benzene on heating with Cl_2 gives A(C_8 H_9CI). A on reaction with alcoholic KOH gives B(C_8 H_8).Compounds A and B are, respectively

Ethyl benzene on heating with Cl_2 gives A(C_8 H_9CI). A on reaction w

1.	Ethyl benzene on heating with Cl_2 gives A(C_8 H_9CI). A on reaction with alcoholic KOH gives B(C_8 H_8).Compounds A and B are, respectively
Answer» `C_6H_5 - CH_2CH_2 CL and C_6H_5 - CH_2 - CH_2-OH ` `C_H_5 - overset(Cl)overset(\|)CH-CH_3 and C_6H_5-overset(OH)overset(\|)CH-CH_3` `C_6H_5 - CH_2CH_2Cl and C_6H_5-CH =CH_2` `C_6H_5 - overset(Cl)overset(\|)CH-CH_3 and C_6H_5 - CH = CH_2 ` Solution :FREE radical chlorination occur at BENZYLIC carbon followed by E-2 elimination REACTION