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Ethyl bromide on treatment with alcoholic KOH givesA. EthyleneB. EthanolC. Acetic acidD. Ethane |
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Answer» Correct Answer - A `underset("bromide")underset("Ethyl")(C_(2)H_(5)Br)+underset("Alcoholic")(KOH)rarr underset("Ethylene")(C_(2)H_(4))+KBr+H_(2)O` This reaction ios known as dehydrohalogenation. |
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