Ethyl chloride (C2H5Cl) is prepared by reaction of ethylene with hydrogen chloride:C2H4(g)+HCl(g)→C2H5Cl(g)△H=−72.3 kJ/molWhat is the value of △U (in kJ), if 98 g of ethylene and 109.5 g of HCl are allowed to react at 300 K?

Ethyl chloride (C2H5Cl) is prepared by reaction of ethylene with hydro

1.	Ethyl chloride (C2H5Cl) is prepared by reaction of ethylene with hydrogen chloride:C2H4(g)+HCl(g)→C2H5Cl(g)△H=−72.3 kJ/molWhat is the value of △U (in kJ), if 98 g of ethylene and 109.5 g of HCl are allowed to react at 300 K?
Answer» Ethyl chloride $(C_{2} H_{5} C l)$ is prepared by reaction of ethylene with hydrogen chloride: $C_{2} H_{4} (g) + H C l (g) \to C_{2} H_{5} C l (g) △ H = - 72.3 k J / m o l$ What is the value of $△ U$ (in $k J$ ), if $98 g$ of ethylene and 109.5 g of $H C l$ are allowed to react at $300 K$ ?