Evaluate∛4096 – InterviewSolution

1.

Evaluate∛4096

Answer»

The prime factors of 4096 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2

Now by grouping into three we get, (2 × 2 × 2) × (2 × 2 × 2) × (2 × 2 × 2) × (2 × 2 × 2)

∴ \(\sqrt[3]{((2)^3 × (2)^3× (2)^3 × (2)^3) }\)

= (2 × 2 × 2 × 2)

= 16

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