Evaluate: 62P3 – InterviewSolution

InterviewSolution

1.

Evaluate: 62P3

Answer»

To find: the value of ⁶²P₃

Formula Used:

Total number of ways in which n objects can be arranged in r places (Such that no object is replaced) is given by,

ⁿP_r = \(\frac{n!}{(n-r)!}\)

Therefore,

⁶²P₃ = \(\frac{62!}{(62-3)!}\)

⁶²P₃ = 62 × 61 × 60 × 59 = 226920

Thus, the value of ⁶²P₃ is 226920.

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