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Evaluate [[a,a^2-bc,1],[b,b^2-ac,1],[c,c^2-ab,1]] |
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Answer» SOLUTION :`[[a,a^2-bc,1],[B,b^2-ac,1],[C,c^2-ab,1]]` =`[[a-b,a^2-bc-b^2+ca,0],[b-c,b^2-ca-c^2+ab,0],[c,c^2-ab,1]]` `(R_1~~R_1-R_2, R_2~~R_2-R_3)` =`(a-b)(b-c)[[1,a+b+c,0],[1,a+b+c,0],[c,c^2-ab,1]]` =`(a-b)(b-c)xx0 (because R_1=R_2)` |
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