1.

Evaluate `|(a+ib,c+id),(-c+id,a-ib)|`

Answer» Here, `A = |[a+ib,c+id],[-c+id,a-ib]|`
`=>A = [(a+ib)(a-ib) - (-c+id)(c+id)]`
`=>A = [a^2-i^2b^2-(i^2d^2 - c^2)]`
As `i^2 =-1`,
`:. A = a^2+b^2+c^2+d^2`


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