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Evaluate by expressing (2-3x+x2)dx from 0 to 1 as limit os a sum |
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Answer» 0∫1 (2 - 3x + x2) dx \(=(2x-\frac{3x^2}2+\frac{x^3}3)^1_0\) = 2 - 3/2 + 1/3 - 0 \(=\frac{12-9+2}6\) = 5/6. |
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