1.

Evaluate :∫dx/1+x2  for x→[1,√3]

Answer»

I = ∫ (1+logx)/x dx

Let 1 + log x = z

1/x dx = dz => I = ∫z2dz

= Z3 / 3 +C =1/3(1 + logx)+ c



Discussion

No Comment Found

Related InterviewSolutions