InterviewSolution
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Evaluate :∫dx/1+x2 for x→[1,√3] |
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Answer» I = ∫ (1+logx)2 /x dx Let 1 + log x = z 1/x dx = dz => I = ∫z2dz = Z3 / 3 +C =1/3(1 + logx)3 + c |
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