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Evaluate each of the following expressions for x = -2, y = -1, z = 3:(i) (x/y) + (y/z) + (z/x)(ii) x2 + y2 + z2 – xy – yz – zx |
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Answer» (i) Given x = -2, y = -1, z = 3 Consider (x/y) + (y/z) + (z/x) On substituting the given values we get, = (-2/-1) + (-1/3) + (3/-2) The LCM of 3 and 2 is 6 = (12 – 2 – 9)/6 = (1/6) (ii) Given x = -2, y = -1, z = 3 Consider x2 + y2 + z2 – xy – yz – zx On substituting the given values we get, = (-2)2 + (-1)2 + 32 – (-2) (-1) – (-1) (3) – (3) (-2) = 4 + 1 + 9 – 2 + 3 + 6 = 23 – 2 = 21 |
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