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Evaluate each of the following:sin-1(sin 12) |
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Answer» sin–1(sin x) = x Provided x ∈\([\frac{-\pi}2,\frac{\pi}2]\)≈ [–1.57,1.57] And in our equation x is 4 which does not lie in the above range. We know sin[2nπ – x] = sin[–x] ∴ sin(2nπ – 12) = sin(–12) Here n = 2 Also 2π–12 belongs in \([\frac{-\pi}2,\frac{\pi}2]\) ∴ sin–1(sin12) = 2π – 12 |
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