1.

Evaluate each of the following:sin-1(sin 12)

Answer»

sin–1(sin x) = x

Provided x ∈\([\frac{-\pi}2,\frac{\pi}2]\)≈ [–1.57,1.57]

And in our equation x is 4 which does not lie in the above range.

We know sin[2nπ – x] = sin[–x]

∴ sin(2nπ – 12) = sin(–12)

Here n = 2

Also 2π–12 belongs in \([\frac{-\pi}2,\frac{\pi}2]\)

∴ sin–1(sin12) = 2π – 12



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