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Evaluate each of the following:sin-1(sin 2) |
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Answer» sin–1(sin x) = x Provided x ∈\([\frac{-\pi}2,\frac{\pi}2]\) ≈ [–1.57,1.57] And in our equation x is 3 which does not lie in the above range. We know sin[π – x] = sin[x] ∴ sin(π – 2) = sin(2) Also π–2 belongs in \([\frac{-\pi}2,\frac{\pi}2]\) ∴ sin–1(sin2) = π–2 |
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