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Evaluate each of the following:\(sin^{-1}(sin 3)\) |
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Answer» sin–1(sin x) = x Provided x ∈ \([\frac{-\pi}2,\frac{\pi}2]\) ≈ [–1.57,1.57] And in our equation x is 3 which does not lie in the above range. We know sin[π – x] = sin[x] ∴ sin(π – 3) = sin(3) Also π–3 belongs in \([\frac{-\pi}2,\frac{\pi}2]\) ∴ sin–1(sin3) = π–3 \(sin^ -1(sin-3)=0.11874839215\) |
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