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Evaluate each of the following:\(sin^{-1}(sin\frac{13\pi}7)\) |
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Answer» We can write \((sin\frac{13\pi}7)\) as \(sin(2\pi-\frac\pi{7})\) As we know sin(2π –θ) = sin(–θ ) So, \(sin(2\pi-\frac\pi{7})\) can be written as \(sin(\frac\pi{7})\) ∴ The equation becomes sin–1\((sin\frac{\pi}7)\) As sin-1(sin x) = x Provided x ∈ \([\frac{-\pi}2,\frac{\pi}2]\) ∴ we can write \(sin^{-1}(sin\frac{\pi}7)=\frac{\pi}7\) |
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