Evaluate i t = Sec 41. Sin 49 + Cos 49,

1.	Evaluate i t = Sec 41. Sin 49 + Cos 49,
Answer» Sec 41× sin(90-41) + cos(90-41)× cosec41 - 2 / 3^1/2 × tan (90-70)× 3^1/2 × tan 70 - 3(1/2 -1)=( sec 41× cos 41 )+( sin 41× cosec 41 )-(2× cot70 × tan70) -3(-1/2)= 1 + 1 - 2 + 3/2= 3/2. Sin(90-x)= cos xCos(90-x) = sin xTan(90-x)= cot xCotx × tanx =1Sin × cosec=1Cos × sec=1

Answer»

Sec 41× sin(90-41) + cos(90-41)× cosec41 - 2 / 3^1/2 × tan (90-70)× 3^1/2 × tan 70 - 3(1/2 -1)=( sec 41× cos 41 )+( sin 41× cosec 41 )-(2× cot70 × tan70) -3(-1/2)= 1 + 1 - 2 + 3/2= 3/2.

Sin(90-x)= cos xCos(90-x) = sin xTan(90-x)= cot xCotx × tanx =1Sin × cosec=1Cos × sec=1

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Evaluate i t = Sec 41. Sin 49 + Cos 49,

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