InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Evaluate indefinite integration. (i) `x=intdt " "` (ii) `int t dt " "` (iii) `x=int (2t) dt" "` (iv) `x=int (t^(2)) dt " "` (v) `x=int (-(2)/(t^3))dt` |
|
Answer» (i) `x=t+c " "` (ii) `x=(t^(2))/(2)+c" "` (iii) `x=(2t^(2))/(2)+c=t^(2)+c` (iv) `x=t^(3)/(3)+c" "` (v) `x=-2intt^(-3)dtrArrx=-2((t^(-2))/(-2))+c=t^(-2)+c` |
|