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Evaluate `int(1-cosx)"cosec"^(2)xdx`A. `tan.(x)/(2)+C`B. `-cot.(x)/(2)+C`C. `2tan.(x)/(2)+C`D. `-2cot.(x)/(2)+C` |
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Answer» Correct Answer - A (a) `int(1-cos x)"cosec"^(2)x dx=int(1-cosx)/(1-cos^(2)x)dx` `=int(1)/(1+cosx)dx=(1)/(2)int sec^(2).(x)/(2)dx=tan.(x)/(2)+C` |
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