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Evaluate:`int(2x-1)/((x-1)(x+2)(x-3))dx` |
Answer» Since all the factors in the denominator are linear, we have `int(2x-1)/((x-1)(x+2)(x-3))dx` `=int[(1)/((x-1)(3)(-2))+(-5)/((-3)(x+2)(-5))+(5)/((2)(5)(x-3 ))]dx` ` = -(1)/(6) log |x-1|-(1)/(3)log|x+2|+(1)/(2)log|x-3|+C` |
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