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Evaluate:`int(2x+3)/(sqrt(x^2+4x+1))dx`

Answer» `int(2x+3)/sqrt(x^(2)+4x+1)dxint((2x+4)-1)/sqrt(x^(2)+4x+1)dx=int(2x+4)/sqrt(x^(2)+4x+1)x-int1/sqrt(x^(2)+4x+1)`dx
`=int(dt)/sqrt(t) -int1/((x+2)^(2)-(sqrt(3))^(2))dx`, where `t=(x^(2)+4x+1)` for Ist integral
`=2sqrt(t)-ln|(x-2)+sqrt(x^(2)+4x+1)|+C=2sqrt(x^(2)+4x+1)-ln|x+2+sqrt(x^(2)+4x+1)|+C`


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