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Evaluate:`int(2x)/((x^2+1)(x^2+2))dx` |
Answer» Let `I=int (2x)/((x^(2)+1)(x^(2)+2))dx` Putting `x^(2)=t` and `2x dx=dt`, we get `I=int (dt)/((t+1)(t+2))` `=int((1)/(t+1)-(1)/(t+2))dt` `=log|t+1|-log|t+2|+C` `=log|x^(2)+1|-log|x^(2)+2|+C` |
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