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Evaluate `int(3x^(2)"tan"(1)/(x)-x"sec"^(2)(1)/(x))dx`. |
Answer» `int(3x^(2)"tan"(1)/(x)-x"sec"^(2)(1)/(x))dx` `=int3x^(2)"tan"(1)/(x)dx-int x"sec"^(2)(1)/(x)dx` `="tan"(1)/(x)x^(3)-int("sec"^(2)(1)/(x))(-(1)/(x^(2)))x^(3)dx- int x "sec"^(2)(1)/(x)dx` `=x^(3)"tan"(1)/(x)+c` |
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